heya friends.....
plzzzz solve this ......
it's urgent ........
right answrr will be marked as brainlist
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HEY FRIEND THE ANSWER IS HERE
PLEASE MAKE IT AS BRAINLIEST
THANK YOU
PLEASE MAKE IT AS BRAINLIEST
THANK YOU
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mehak021:
wrng answer
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Hey user
Here is your answer :-
Let the numerator of the fraction be " m "and the denominator be " n " .
The sum of numerator and denominator is 3 less than twice the denominator
By this condition we get equation,
m + n = 2n - 3
》m - n = - 3. . . . ( 1 )
If both the numerator and denominator are decreased by 1 , the numerator becomes half the denominator.
By this condition we get equation ,
2( m - 1 ) = n - 1
》2m - 2 = n - 1
》2m - n = 1. . . . ( 2 )
Subtracting equation ( 1 ) from equation ( 2 ) we get ,
m = 4
Putting m = 4 in equation ( 1 )
4 - n = - 3
》n = 4 + 3
》n = 7
So the required fraction is 4/7 .
Thank you .
Here is your answer :-
Let the numerator of the fraction be " m "and the denominator be " n " .
The sum of numerator and denominator is 3 less than twice the denominator
By this condition we get equation,
m + n = 2n - 3
》m - n = - 3. . . . ( 1 )
If both the numerator and denominator are decreased by 1 , the numerator becomes half the denominator.
By this condition we get equation ,
2( m - 1 ) = n - 1
》2m - 2 = n - 1
》2m - n = 1. . . . ( 2 )
Subtracting equation ( 1 ) from equation ( 2 ) we get ,
m = 4
Putting m = 4 in equation ( 1 )
4 - n = - 3
》n = 4 + 3
》n = 7
So the required fraction is 4/7 .
Thank you .
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