Math, asked by Anonymous, 1 year ago

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Prove that : -
cot x cot 2 x - cot 2 x cot 3 x - cot 3x cot x = 1


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Answers

Answered by menakatatap49utf
4
L.H.S=cot x. cot 2x - cot 2x. cot3x - cot x. cot3x

=cot x. cot 2x - cot3x(cot 2x +cot x)

=cotx .cot 2x - cot (x+2x) .(cot 2x+ cot x)                       [we can write cot3x as cot(x+2x)]

=cotx.cot2x- {(cot x. cot 2x -1)/(cot x + cot 2x)}.(cot x + cot 2x)            [since cot(a+b)=(cot a. cot b -1)/(cot b+cot a)]

=cot x. cot 2x -cot x. cot 2x +1

=1

Answered by samikshasingh224
4
Cot 3x=cot (2x+x)
Now apply the formula of cot (x+y)
Hope it help u
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