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From a circular metal sheet of radius 9cm, a circle of radius 4cm is removed. Find the area of the remaining sheet. (Take π=3.14)
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Answered by
71
area of remaining sheet=area of circle having radius 9 cm-area of circle having radius 4 cm
area of circle1=3.14×81=254.34
area of circle2=3.14×16=50.24
therefore required area of remaining sheet =254.34-50.24 =204.10sq cm
hope you can understand ☺☺
area of circle1=3.14×81=254.34
area of circle2=3.14×16=50.24
therefore required area of remaining sheet =254.34-50.24 =204.10sq cm
hope you can understand ☺☺
Answered by
10
Answer:
Area of the remaining sheet= area of circle having radius 9cm - area of circle having radius 4cm
=> Area of circle 1 = 3.14 × 81 = 254.34
=> Area of circle 2 = 3.14 × 16 = 50.24
(•°•) => Required area of of the remaining sheet.
=> 254.34 - 50.24
=> 204.1 cm sq
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