Question

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A peacock in sitting on the top of a pillar, which is 9m high . From a point 27 m away from the bottom of pillar , a snake is coming to its hole at the base of pillar . Seeing the snake the peacock pounces on it. If their speeds are equal, at what distance from the whole is snake caught ?? ​

Answer 1

Answer:

Distance from hole =12m

Explanation:

As speed of both peacock and snake is same

so distance covered by both of them will be same

So let distance be x.

Snake will be at distance of 27-x.

Peacock distance will be equal to:

(9)^2+ (27-x)^2=(x)^2

81+729+x^2- 54x =x^2

x=810/54

x=15m

Distance covered by both of them:15m

Distance from hole : 27-15 =12m

Please mark it as brainliest.

Answer 2

Answer:

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Step-by-step explanation:

Let the distance covered by the peacock be AC = x m Hence the distance covered by the snake is DC = x m In right ΔABC, by Pythagoras theorem we have AC2 = AB2 + BC2 x2 = 92 + (27 – x)2 ⇒ x2 = 81 + 729 – 54x + x2 ⇒ 54x = 810 ∴ x = 15