heya guys back with a new interesting question please answer it . No spam answers
Attachments:
Answers
Answered by
1
The reaction of AgNO3 with H2S can be represented as follows:
2AgNO3 + H2S → Ag2S + 2HNO3
Here, 1 mole of H2S reacts with 2 moles of AgNO3
Hence,
The ratio of amount of H2S required to precipitate all the metal ions from 100 mL 1M AgNO3 is,
1 H2S : 2 AgNO3
The reaction of CuSO4 with H2S can be represented as follows:
CuSO4 + H2S → CuS + H2SO4
Here, 1 mole of H2S reacts with 1 mole of CuSO4
Hence,
The ratio of amount of H2S required to precipitate all the metal ions from 100 mL 1M CuSO4 is,
1 H2S : 1 CuSO4
2AgNO3 + H2S → Ag2S + 2HNO3
Here, 1 mole of H2S reacts with 2 moles of AgNO3
Hence,
The ratio of amount of H2S required to precipitate all the metal ions from 100 mL 1M AgNO3 is,
1 H2S : 2 AgNO3
The reaction of CuSO4 with H2S can be represented as follows:
CuSO4 + H2S → CuS + H2SO4
Here, 1 mole of H2S reacts with 1 mole of CuSO4
Hence,
The ratio of amount of H2S required to precipitate all the metal ions from 100 mL 1M CuSO4 is,
1 H2S : 1 CuSO4
Similar questions