Question

Heya guys I need explanation

Evaluate:
Cos41°/Sin49° +Sec37°/Cosec53°???​

Answer 1

Answer:

Hello mate!

Kindly check the above picture for your answer..

Hope it helps you

Answer 2

Answer:

2

Step-by-step explanation:

$\frac{ \cos41 }{ \sin49} + \frac{ \sec37 }{ \csc53 } \\ \\ = > \frac{ \cos41 }{ \sin(90 - 41) } + \frac{ \sec37}{ \csc(90 - 37) } \\ \\ = > \frac{ \cos41 }{ \cos41} + \frac{ \sec37}{ \sec37 } \\ \\ = > 1 + 1 = 2 \\ \\ \sin(90 - \alpha ) = \cos \alpha \: and \: \csc(90 - \alpha ) = \sec \alpha$