Question

Heya Guys...
Now test up ur IQ Level..
In a truck there are 10 boxes, each 10 balls, of mass 10 gm each. But by mistake one box contains, 10 balls of mass 9 gm. U can use measuring scale just for once, how will u use that depends on u... But u have to identify the box containing that 9 gm weighed box.
How can u find it??​

Answer 1

Thinking.....

Hmmmm....

Hmmmmm....

Heya... I've a doubt!

➡️Can we open the box and take some balls out? Is it allowed?

If it is allowed, then I think the following step'll work out:

➡️As it is given there are 10 boxes...

So...any of the boxes can be the defective one.

So, lemme call box 1 as A

box 2: B

box 3: C

.........

box 10: J

So....

I'm totally leaving box A.

Lemme pick 1 ball from box B

2 balls from box C

3 balls from box D

.......

9 balls from box J

So, totally from 9 boxes(I left box A), I picked 1+2+3+4+5+6+7+8+9= (9/2)(1+9) =4.5×10=45 balls.

So....I took all these balls and placed them on the weighing machine(or weighing spring).

As we know one box contains defective balls.

So if box A was the defective one, since I haven't take any balls from box A, the rest 45 balls would totally weigh 45×10g= 450grams.

So...if 450g is shown on the weighing machine, we can conclude that box A is defective!

If box B was defective, since I took 1 ball from it, then the weighing measurement would have been 450g -1= 449 grams.

If box C was defective, since I took 2 ball from it, then the weighing measurement would have been 450g -2=448g

If box D was defective, since I took 3 ball from it, then the weighing measurement would have been 450g -3=447g

Similarly,

if box E= weight displayed= 446grams.

Box F= 445

box G= 444

H=443

I=442

J=441grams

So by just weighing the 45 balls for one time, I can easily point out which box is the defective one...

Answer 2

.............just simple.................

Consider all 10 boxes have 10 gm balls

then..,

by substracting ,...100gms( that is weight of one box) from the weight of the truck ....for the first time. u will get the. weight that matches with your consideration..( that is. ..what u have calculated :weight of truck+ wight of all boxes(1000gm) ......,(100 gm each as considered) minus 100g).the box at which it mismathches( as 90gms) that is the answer...................

...... MARK AS BRAINLIEST.......