Question

❤ heya...guys!!!❤

One question for you all...my dear mates


Show that for a projectile the angle between the velocity and then x-axis as a function of time is given by

Theta(t) =
tan inverse[ v{y-axis}-Gt ] / v{x-axis}

Please solve it if u can...,❤

Perfect answer is needed
I will mark you as brainliest...

Help me my dear mates with this question❤❤

Answer 1

Hey user here is your answer.......... ⤵☺
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,
,
,Let  and respectively be the initial components of the velocity of the projectile along horizontal (x) and vertical (y) directions.

Let and respectively be the horizontal and vertical components of velocity at a point P.

Time taken by the projectile to reach point P = t

Applying the first equation of motion along the vertical and horizontal directions, we get:

(b) Maximum vertical height, hm=u02sin2θ2g    ...(i)

Horizontal range, R=u02sin2θg    ...(ii)

Solving equations (i) and (ii), we get:

hmR=sin2θ2sin2θ=sin2θ4sinθcosθ=sinθ4cosθ⇒hmR=Tanθ4⇒θ=Tan-14hmR

#see the attached graph , then you will get it right...❗❗✌✌

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Regards
Riyan...✌✌

Answer 2

hope this will help you.. :-)