Question

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✔Calculate the mass of oxygen which contains same number of atoms as are present in 4.6g of sodium. ( Atomic Mass of Na= 23 and O = 16 )

Answer 1

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Mass of Na = 4.6 g

Moles of Na =mass / molar mass

Moles of Na = 4.6 /23

Moles of Na = 0.2 mol

Now ......

Moles of Na = Number of atoms of Na / Avagadro number

Number of atoms of Na= Moles of Na × Avagadro number

Number of atoms of Na = 0.2 × 6.023 × 10^23

Number of atoms of Na = 1.2 ×10^23

NOW ......

It is given in question that O2 has same atoms as that in 4.6g of Na

So number of atoms of O2 = 1.2 × 10^23

Moles of O2 = Number of atoms of O2 / Avagadro number

Moles of O2 = 1.2 ×10^23 /6.023 ×10^23

Moles of O2 = 0.19mol

Now ........

Moles of O2=mass / molar mass

Mass of O2 = moles × molar mass

Mass of O2 = 0.19 × 32

$\huge\pink{Mass of O2 = 6.08 g }$

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Answer 2

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Mass of Na = 4.6 g

Moles of Na =mass / molar mass

Moles of Na = 4.6 /23

Moles of Na = 0.2 mol

Now ......

Moles of Na = Number of atoms of Na / Avagadro number

Number of atoms of Na= Moles of Na × Avagadro number

Number of atoms of Na = 0.2 × 6.023 × 10^23

Number of atoms of Na = 1.2 ×10^23

NOW ......

It is given in question that O2 has same atoms as that in 4.6g of Na

So number of atoms of O2 = 1.2 × 10^23

Moles of O2 = Number of atoms of O2 / Avagadro number

Moles of O2 = 1.2 ×10^23 /6.023 ×10^23

Moles of O2 = 0.19mol

Now ........

Moles of O2=mass / molar mass

Mass of O2 = moles × molar mass

Mass of O2 = 0.19 × 32