Physics, asked by kaete, 1 year ago

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A torch bulb is rated 5V &500mA. Calculate (i) it's power (ii) its resistance and (iii) the energy consumed if this bulb is lighted for 4 hours.

Answers

Answered by Anonymous
5

Here Is Your Ans ⤵

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Given : -

Potential difference = V = 5V

Current = I = 500mA = 500 / 1000 A = 0.5 A

I) Power = V X I

= 5 x 0.5 = 5 x 5 / 10 = 2.5 W

II) Resistance = R =?

By Ohm's law : V = IR

R = V/I

R = 5/0.5

= 50 / 5 = 10 ohms

III) Energy consumed when it is lighted for 4 hours

Energy = Power x time

t = 4 hrs= 4 x 60 x 60

= 2.5 x 4 x 60 x 60

= 36000 joules/sec

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Answered by hardikrakholiya21
1

Hello friend.

Given :

Potential difference =V=5V

Current =I= 500mA=500x/1000 A=0.5 A

I) Power = V X I

= 5x0.5 =5x5/10=2.5 W

II)Reistance =R=?

By Ohm's law: V=IR

R=V/I

R=5/0.5 

=50/5 =10 ohms

III)Energy consumed when it is lighted for 4 hours

Energy =Power x time

t=4hrs=4x60x60

=2.5x 4x60x60

=36000joules/sec

hope it's helpful for you...

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