Math, asked by IƚȥSɯҽҽƚCαɳԃყ, 10 months ago

Heya guys✌
Plz help me out with this question☺
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Answers

Answered by ArsheyaK
1

p - q = 9

pq = 36

By p - q = 9, we find out,

p = 9 + q

Therefore,

(9 + q)q = 36

9q + q^2 = 36

q = 3

Therefore,

p = 9 + 3 = 12

(i) p + q

12 + 3 = 15

(ii) p^2 - q^2

12^2 - 3^2 = 144 - 9 = 135

Hope you found this helpful :)

Answered by BrainlyConqueror0901
5

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{p+q=-15}}}

\green{\tt{\therefore{p+q=15}}}

\green{\tt{\therefore{p^{2}-q^{2}=-135}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\  \tt:   \implies p - q = 9 \\  \\ \tt:   \implies pq = 36 \\  \\  \red{\underline \bold{To \: Find:}}\\ \tt:   \implies p + q = ? \\  \\ \tt:   \implies  {p}^{2}  -  {q}^{2}  = ?

• According to given question :

 \tt:  \implies p - q = 9 \\  \\ \tt:  \implies p = 9 + q -  -  -  -  - (1) \\  \\ \tt:  \implies pq = 36 \\ \\  \text{Putting \: value \: of \: p}  \\ \tt:  \implies  (9 + q)q = 36 \\  \\ \tt:  \implies 9q +  {q}^{2}  = 36 \\  \\ \tt:  \implies  {q}^{2}  + 9q - 36 = 0 \\  \\ \tt:  \implies  {q}^{2}  + 12q - 3q - 36 = 0 \\  \\ \tt:  \implies q(q + 12) - 3(q + 12) = 0 \\  \\ \tt:  \implies(q - 3)(q + 12) = 0 \\  \\  \green{\tt:  \implies q = 3 \: and \:  - 12} \\  \\  \text{Putting \: value \: of \: q  = 3\: in \: (1)} \\  \tt:  \implies p = 9 + 3 \\  \\  \green{\tt:  \implies p = 12} \\  \\  \text{Putting \: value \: of \: q =  - 12 \: in  \: (1)} \\   \tt:  \implies p = 9  - 12 \\  \\  \green{\tt:  \implies p =  - 3}

 \tt \circ \: p = - 3 \: and \: q =  - 12 \\  \\  \bold{For \: finding \: value} \\  \green{ \tt:  \implies p + q =  - 3 - 12 =  - 15} \\  \\  \bold{For \: finding \:another \: value} \\  \tt:  \implies  {p}^{2}  -  {q}^{2}  \\  \\ \tt:  \implies (p + q)(p - q) \\  \\ \tt:  \implies ( - 3 - 12)( - 3 + 12) \\  \\ \tt:  \implies  - 15 \times 9 \\  \\  \green{\tt:  \implies  - 135}

 \tt \circ \: p = 3 \: and \: q  = 12 \\  \\  \bold{for \: finding \: value} \\   \green{\tt:  \implies p + q = 3 + 12 = 15 }\\  \\  \bold{For \: finding \: another \: value} \\  \tt:  \implies  {p}^{2}   -  {q}^{2}  \\  \\  \tt:  \implies (p + q)(p - q) \\  \\ \tt:  \implies 15 \times (3 - 12) \\  \\ \tt:  \implies 15 \times  - 9 \\  \\  \green{\tt:  \implies  - 135}

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