Math, asked by angel369, 1 year ago


Heya guys solve this
its urgent
rationalise 1/√5-2​

Answers

Answered by Anonymous
4

Answer:

1/√5 - 2 × √5 +2/√5+2

√5 + 2 / (√5)^2-4

√5 + 2 / 5-4

√5 +2

hope it's helpful

Answered by Anonymous
4

Answer \:  \\  \\  \frac{1}{ \sqrt{5}  - 2}  \\  \\  \frac{1}{ \sqrt{5} - 2 }  \times  \frac{ \sqrt{5}  + 2}{ \sqrt{5}  + 2}  \\  \\  \frac{ \sqrt{5} + 2 }{ (\sqrt{5}  - 2) \times ( \sqrt{5}  +2)}  \\  \\  \frac{ \sqrt{5}   + 2}{( \sqrt{5} ) {}^{2} -  (2) {}^{2}  }  \\  \\  \frac{ \sqrt{5}   +  2}{5 - 4}  \\  \\   \frac{ \sqrt{5}  +  2 }{1}  \\  \\  \sqrt{5}  + 2 \\  \\ NOTE \:  \\  \\ (a + b)(a - b) = a {}^{2}  - b {}^{2}


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Anonymous: bangun
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