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Try the above question in the pic.
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first we need to take out the parallel effective resistance of the two resistors
Rp=R1×R2÷R1+RE
15×10÷15+10
150÷25
= 6 ohm
now current (I) =v÷R
6÷6=1 ampere
now voltage across the two resistors = I × R
6×1=6V
Rp=R1×R2÷R1+RE
15×10÷15+10
150÷25
= 6 ohm
now current (I) =v÷R
6÷6=1 ampere
now voltage across the two resistors = I × R
6×1=6V
HridayAg0102:
ok
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