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✨ CALCULATE THE B) PART ONLY.
❌ NO SPAMS ALLOWED. . . . . .
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JinKazama1:
Answer is 55 ??
Answers
Answered by
1
is The answer is 55...moles...
use simple unitary method.
11 mole of o atoms are present in 1mole of ZnSO4.7H2O
;55moles of o atoms are present in 5Moles of ZnSO4.7H2O
use simple unitary method.
11 mole of o atoms are present in 1mole of ZnSO4.7H2O
;55moles of o atoms are present in 5Moles of ZnSO4.7H2O
solution also needed..... PLZ give it
use simple unitary method
sry but it is ur duty to provide the questioner with solution
koi baat ni
its ok
Answered by
1
Final Answer :55
Steps:
1) No. of atoms of O in given Compound is
4 + 7*1 = 11 .
=> No. of moles of O in 1 mole of given compound is 11moles.
=> No. of moles of O in 5 moles of given compound is 5 * 11 = 55 .
So, Required No. of Moles of Oxygen atom is 55 moles.
Steps:
1) No. of atoms of O in given Compound is
4 + 7*1 = 11 .
=> No. of moles of O in 1 mole of given compound is 11moles.
=> No. of moles of O in 5 moles of given compound is 5 * 11 = 55 .
So, Required No. of Moles of Oxygen atom is 55 moles.
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