Math, asked by tanvi524, 9 months ago

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Answers

Answered by Anonymous
2

Answer:

Hey mate here is your answer....

67 is the answer

Step-by-step explanation:

Firstly,

consider

the quadrilateral as x

banana as a

clock as m

Now let us solve

x+x+x=45

3x=45

x=15

Now for second one

2a+15=23

2a=23-15=8

a=4

Now for third case

4+2m=10

2m=10-4=6

m=3

Now your answer is solved

3+4+4×15

Apply BODMAS rule here

3+4+60

67

Hope it helps you....

Answered by Unknown0708
2

Answer:

In the first equation there are 3 shapes square, pentagon and hexagon

1st equation will be (4+5+6)+(4+5+6)+(4+5+6) that is the side of each figure

It's total is 45 Now 1 shape will be 15

2nd equation is 4 bananas+4 bananas+15 =23

8 bananas =8

Banana= 1

3rd equation is 4 +3(time in clock) +3(same) =10

Now last equation

2(time in clock) + 3 (no. of bananas) +3(no.of bananas)+ 11( pentagon +hexagon that is 5+6 as there is no square)

Now by applying bodmas

2+3+3*11

2+3+33

38 is the answer.

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