Question

heya....


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Help!

❌No spams ​

Answer 1

Angle OPQ = Angle OQP (Because OP = OQ, radii)

Therefore, in isosceles ∆OPQ, Angle POQ = 180 - 2 (OPQ) = 180 - 60 = 120°

Sector angle, ẞ = 120°

Draw OM perpendicular to PQ.

Perpendicular drawn from centre to chord bisects the chord, Therefore, PM = MQ = 7 cm.

In ∆ OMP, cos 30° = PM/OP

→ √3/2 = 7/OP

Therefore, OP = 14/√3

Therefore, radius of circle (r) = 14/√3 cm.

Area of shaded region = ẞ/360° π r² - 1/2 r² sin ẞ

= 1/3 × 3.141 × 196 / 3 - 1/2 × 196 / 3 × √3/2

= 0.349 × 196 - 49 √3/3

= 68.404 - 28.25

= 40.14 cm²

(Answer)

Answer 2

hey mate here is your answer.