Physics, asked by DüllStâr, 6 months ago

Heya!!!!
help please (it's easy)
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Answers

Answered by nirman95
8

Given:

Pressure in a water pipe on the ground floor of a building is 10,000 Pa.

To find:

Pressure of water on 1st floor which is at a height of 3 metres.

Calculation:

General expression for pressure of a liquid column at a depth d is as follows:

 \boxed{ \sf{P =  \rho \times g \times d}}

  • Here \rho is density , "g" is gravity and "d" is depth.

Let the total height of building be h :

At ground floor:

 \therefore \:  \rho \times g \times h = 100000

 =  >  \: 1000 \times 10 \times h = 100000

 =  >  \: 10000 \times h = 100000

 =  >  \:  h = 10 \: metre

Now , the 1st floor is at a height of 3 metres , so it's depth from top floor is (10 - 3) = 7 metres.

Let pressure at 1st floor be P_(1):

 \therefore \: P_{1} =  \rho \times g \times h_{1}

 =  > \: P_{1} =  1000 \times 10 \times (10 - 3)

 =  > \: P_{1} =  1000 \times 10 \times 7

 =  > \: P_{1} =  70000 \: Pa

So, pressure at 1st floor is 70,000 Pascal.

Hope It Helps.

Answered by Talentedgirl1
3

Answer:

Given:

Pressure in a water pipe on the ground floor of a building is 10,000 Pa.

To find:

Pressure of water on 1st floor which is at a height of 3 metres.

Calculation:

General expression for pressure of a liquid column at a depth d is as follows:

</p><p>\boxed{ \sf{P = \rho \times g \times d}} </p><p>

Here

\rhoρ is density , "g" is gravity and "d" is depth.

Let the total height of building be h :

At ground floor:

\therefore \: \rho \times g \times h = 100000∴ρ×g×h=100000

= &gt; \: 1000 \times 10 \times h = 100000=&gt;1000×10×h=100000</p><p></p><p>= &gt; \: 10000 \times h = 100000=&gt;10000×h=100000</p><p></p><p>= &gt; \: h = 10 \: metre=&gt;h=10metre

Now , the 1st floor is at a height of 3 metres , so it's depth from top floor is (10 - 3) = 7 metres.

Let pressure at 1st floor be P_(1):

\therefore \: P_{1} = \rho \ \: P_{1} = 1000 \times 10 \times (10 - 3)=&gt;P

1

=1000×10×(10−3)

=

&gt; \: P_{1} = 1000 \times 10 \times 7=&gt;P

1

=1000×10×7

=

 &gt; \: P_{1} = 70000 \: Pa=&gt;P

1

=70000Pa

So, pressure at 1st floor is 70,000 Pascal.

Hope It Helps.

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