Heya here with my question
The graph of the linear equation 2x + 3y = 6 cuts the y axis at the point
a) (2,0)
b) (0,3)
c) (3,0)
d) (0,2)
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its on Y-axis. so x=0
→(2×0)+3y=6
→y=6/3=2
so coordinte =(0.2)
→(2×0)+3y=6
→y=6/3=2
so coordinte =(0.2)
Leukonov:
so X coordinate must be 0. Right?
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