Question

heya!

If an object at a distance 6.4×10^6m from the centre of earth weighs 10N, what will be its weight if it is shifted to the distance 1.28 ×10 ^7m from the center of the earth? ​

Answer 1

here is the solution!

mark as brainlist!!!

Answer 2

Nice question!!

Thanks For asking!!

Given:-

Mass of earth:-

$6 \times {10}^{24} kg$

Radius of earth:-

$6.4 \times {10}^{6} m$

Since, the weight of object is 10 N

By using weight formula,

$w = m \times g$

$10 = m \times 10m {s}^{ - 1}$

$m = 1kg$

Now the mass of object is 1 kg.

Since ,object is shifted to a distance of

$1.28 \times {10}^{7} m$

Now,by using gravity formula ,

$g = \frac{gm}{{r}^{2} }$

putting the values in equation,

$g = 6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} \div ( {6.4 \times {10}^{6} })^{2}$

by further calculation we get,

$g = 2.5m {s}^{2}$

Now Weight of object is

W=M×g

W=1 × 2.5

W= 2.5 N ans.....