Heya!!!
If , x = root over 2 + 1
then , find the value of x^2 + 1 / x^2
Answers
Answered by
0
ᴇʟʟᴏ!!
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
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ɢɪᴠᴇɴ , x = ( √2 + 1 )
ᴀɴᴅ ,
1 / x = 1 / ✓2+ 1
= ( √2 - 1 ) / ( √2 + 1 ) ( √2 - 1 )
= ( √2 - 1 ) / 2 - 1
= ( √2 - 1 )
sᴏ ,
x + 1 / x [ • ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs ᴏғ x ᴀɴᴅ 1 / x ]
= ( √2 + 1 ) + ( √2 - 1 )
= 2 √2
ɴᴏᴡ ,
x^2 + 1 / x^2
= ( x + 1 / x )^2 - 2 . x . 1 / x
= ( 2 √2 )^2 - 2
= 4 × 2 - 2
= 8 - 2
= 6
sᴏ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴛʜᴇ ғᴏʟʟᴏᴡɪɴɢ ɪs 6.
__________________________
ʜᴏᴘᴇ ᴛʜɪs ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ!
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
_____________________
ɢɪᴠᴇɴ , x = ( √2 + 1 )
ᴀɴᴅ ,
1 / x = 1 / ✓2+ 1
= ( √2 - 1 ) / ( √2 + 1 ) ( √2 - 1 )
= ( √2 - 1 ) / 2 - 1
= ( √2 - 1 )
sᴏ ,
x + 1 / x [ • ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs ᴏғ x ᴀɴᴅ 1 / x ]
= ( √2 + 1 ) + ( √2 - 1 )
= 2 √2
ɴᴏᴡ ,
x^2 + 1 / x^2
= ( x + 1 / x )^2 - 2 . x . 1 / x
= ( 2 √2 )^2 - 2
= 4 × 2 - 2
= 8 - 2
= 6
sᴏ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴛʜᴇ ғᴏʟʟᴏᴡɪɴɢ ɪs 6.
__________________________
ʜᴏᴘᴇ ᴛʜɪs ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ!
Answered by
1
x=root 2+1
square both side
so x square is =3
now put these value in this
sooo
3+1/3=4/3
is the correct answer
hope you understand mark me as brilliant
square both side
so x square is =3
now put these value in this
sooo
3+1/3=4/3
is the correct answer
hope you understand mark me as brilliant
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