Question

Heya !!

In ∆ ABC , AD , BE , CF are medians then prove that

4(Sum of medians)> 3 (Sum of sides)

Answer 1

Question :

In ∆ ABC , AD , BE , CF are medians then prove that

4(Sum of medians)> 3 (Sum of sides)

Solution :

We have to use the concept that of the intersection of medians .

We know that medians of any triangle divides each other into the ratio of 2:1.

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