Question

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Answer 1

that's the answer hope it helps you

Answer 2

Given Object distance u = -20cm.

Given radius of curvature R = 30cm.

Given Height of object = 5cm.

We know that Radius of curvature = 2 * Focal length

= > R = 2 * f

Then f = R/2

            = 30/2

            = 15cm.


Now,

We know that Mirror formula;

= > 1/v = 1/f - 1/u

= > 1/v = 1/15 - 1/-20

           = 1/15 + 1/20

           = (4 + 3)/60

           = 7/60.


Then v = 60/7

            = 8.57cm.


Now,

Magnification m = -v/u

                            = -8.57/-20

                            = 0.42.



Image size h2 = m * h1

                        = 0.428 * 5

                        = 2.15cm.


Therefore the image is virtual, erect and height of 2.15cm is formed.


Hope this helps!