Question

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JUST ANSWER THIS

Answer 1

this is class 10 example question so understand from there

Answer 2

Answer:  48 square cm

Step-by-step explanation:

Since, the curved surface or lateral area of frustum,

$A=\pi \times(r_1+r_2) \times s$

Where, $r_1$ and $r_2$ are the radius of the bases of the frustum,

While, s be the slant height of the frustum,

Here, The circumference of the circular bases are 18 and 6 cm,

Let $r_1$ and $r_2$ be the radius of the larger base and smaller base respectively,

⇒ $2\pi r_1=18$

⇒ $r_1 = \frac{9}{\pi}$

Also,  

$2\pi r_2=6$

⇒ $r_2 = \frac{3}{\pi}$

Again it is given that s = 4 cm,

Thus, the curved surface area of the given frustum,

$A=\pi(\frac{9}{\pi}+\frac{3}{\pi})\times 4$

$=12\times 4$

$=48$ square cm.

Hence, the curved surface area of the given frustum is 48 square cm.