HEYA...... KARTIK HERE
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Answered by
7
reslt.force
vector f=vect.f1+vect.f2
=2i^+2j^+3i^+4k^
=5i^+2j^+4k^
then magnitude of resultant =root of(5^2+2^2+4^2)
root of(25+4+16)
=........(45)
angle bw f1 and f2
since f1.f2=magnitude of f1 *magn.of f2*cos(theta)
this is dot product of vectors.
6=root of(8)*root of(25)*cos(theta)
6/(5*2*rootof(2) =cos(..)
then theta=cos inverse(3×root(2)/10)
i hope you got it till now if yes then tell me so that i can send your 3rd answer.
otherwise ask your problem.
vector f=vect.f1+vect.f2
=2i^+2j^+3i^+4k^
=5i^+2j^+4k^
then magnitude of resultant =root of(5^2+2^2+4^2)
root of(25+4+16)
=........(45)
angle bw f1 and f2
since f1.f2=magnitude of f1 *magn.of f2*cos(theta)
this is dot product of vectors.
6=root of(8)*root of(25)*cos(theta)
6/(5*2*rootof(2) =cos(..)
then theta=cos inverse(3×root(2)/10)
i hope you got it till now if yes then tell me so that i can send your 3rd answer.
otherwise ask your problem.
mahendrachoudhary123:
do you want 3rd?
Answered by
3
1 St part =F1+F2. Nd third part will become F1. F2 upon mod of F2
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