Question

Heya mate plz answer......It's Urgent ^_^

A metal ball of mass 5 kg falls from a height of 490 m. how nice time it will take to reach the ground ? (g=9.8 m/s)

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Answer 1

answer is 10 seconds by using newtons second equation

s= ut + 1/2 gt square

here s = height =490
g=9.8 u = initial velocity =0
so
490=0×t+ 1/2× 9.8×t square
490= 0+4.9×t sqare
t square =490/4.9
t square =100
t =10

mass does not matter in free fall

Answer 2

Heya Friend, Here Is the Answer Indeed,

Given is mass(m) = 5kg ( Doesn't matter, since gravitational force on any object is independent of mass).

Height(h) = 490 m.

Now, we have to just apply Newton's Second equation of motion,{ h = ut + 0.5 *at^2}

490=0+0.5*9.8*t^2

490/(0.5*9.8)=t^2

490/(4.9)=t^2

100=t^2

√(100)=t

10=t

or t=10 seconds.

Hope it helps...

#Phenomenal...

Sorry 4 late answers, I was experiencing some real connection issues before some moments...