HEYA MATE...
Jo apko aata hai vo kr dijiye plzzz tmrw is my exam....
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3
n (S) = 540
let event A be no. of defected bulbs
n (A) = 22
P (A) = n (A)/n (S)
= 22/540
= 11/270
let event B be no. of non defective bulbs
n (B) = 518
P (B) = n (B)/n (S)
= 518/540
= 259/270
hope it helps....
let event A be no. of defected bulbs
n (A) = 22
P (A) = n (A)/n (S)
= 22/540
= 11/270
let event B be no. of non defective bulbs
n (B) = 518
P (B) = n (B)/n (S)
= 518/540
= 259/270
hope it helps....
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ria2003:
in question 3 no of total bulbs is not clear
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2
hlo queen u should ask each question one by one like this no one is going to answer
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