Question

Heya Mates..✌✌
$0|v€ this plzzz...


NO SPAm⚠⚠⚠⚠​

Answer 1

here is your answer sis . hope it helps

the answer is 127.5° and 52.5°

Answer 2

ok let's see

According to the figure

As (AOBP) is a quadrilateral

ANGLE APB+ANGLE PAO+ANGLE AOB+ANGLE OBD=360°

AS PA AND PB ARE TANGENTS ANGLE PAO AND ANGLE OBP =90°

SO

75°(GIVEN)+90°+90°+ANGLE AOB=360°

SO

ANGLE AOB

=360°-180°-75°

=105°

AND AS WE KNOW THAT ANGLES FROM SAME SEGMENT OF THE CIRCLE ON THE CENTRE IS TWICE THEN THE ANGLE ON THE CIRCUMFERENCE ON OTHER SIDE .

SO

ANGLE AOB

=2(ANGLE AQB)

ANGLE AQB=105°/2=52.5°

AND AS A M B O IS A CYCLIC QUADRILATERAL

ANGLE AQB + ANGLE AMB

= 180°

so

ANGLE AMB

=180°-52.5°

=127.5°

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