Question

HEYA MATES AND MY DEAR ONES PLS SOLVE THIS

Answer 1

Step-by-step explanation:PQO=LQO=90°

SOQ=LQO-LQS

SOQ=40°

SIMILARLY

SRO=30

WE KNOW

OQ,OS,OR are equal radi

There for we have 2 isosceles triangle

So

QSR=40+30=70

if it help you then plz mark it as brainliest.

Answer 2

Answer:

angle QSR = 70°

Step-by-step explanation:

We know that the tangent to a circle is perpendicular to the circle's radius through the point of contact on the circle's circumference.

Thus, angle OQL = angle ORM = 90°

As given,

angle SQL + angle OQS = 90°

50° + angle OQS = 90°

angle OQS = 40°

In ∆ OQS, OQ = OS ( radii )

Thus, angle QSO = angle OQS = 40°

Hence, angle QSO = 40° ---- ( 1 )

Also,

angle SRM + angle ORS = 90°

60° + angle ORS = 90°

angle ORS = 30°

In ∆ ORS,

OR = OS

Thus, angle OSR = angle ORS = 30°

Hence, angle OSR = 30° ---- ( 2 )

angle QSR = angle QSO + angle OSR

From ( 1 ) and ( 2 ),

angle QSR = 40° + 30°

angle QSR = 70°