Question

Heya mates !!

Find the number and its two parts if a number is divided into two parts such that one is 14 more than other and two parts are in the ratio 7 : 5 .

Answer 1

$\huge{ \mathcal{ \purple{ \boxed{Solution \: :-}}}}$



Let the first part be x

Let the second part be x + 14

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According to the question,

x + $\dfrac{14}{x}$ = $\dfrac{7}{5}$

5(x + 14) = 7x

5x + 70 = 7x

70 = 7x - 5x

2x = 70

x = $\dfrac{70}{2}$

x = 35

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1st part of the number is x

$\therefore{}$ 1st part = $\underline{ \underline{35}}$


2nd part is x + 14

$\therefore{}$ 2nd art => 35 + 14 = $\underline{ \underline{49}}$

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Original number => 35 + 49 = $\underline{ \underline{84}}$

Answer 2

Let the required number be a,

According to the question, if a number is divided into two parts such that one is 14 more than other and two parts are in the ratio 7 : 5

Let,  

    first part be x

    other part be ( x + 14 ), 14 more than other

Ratio of the two parts = 7 : 5

= > ( x + 14 ) : x = 7 : 5

= > ( x + 14 ) / x = 7 / 5

= > 5( x + 14 ) = 7x

= > 5x + 70 = 7x

= > 70 = 7x - 5x

= > 70 = 2x

= > 70 / 2 = x

= > 35 = x

Therefore, first part of a = x  = 35

                   second part of a = x + 14

                                                = 35 + 14

                                                 = 49

a = sum of both the parts

a = first part + second part

a = 35 + 49

a = 84

Therefore, required number is 84 and parts are 49 and 35 .

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