Question

Heya mates.... Please help me in this question...

Answer 1

Hey sis here is your answer.........!!☺❗⤵⬇

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Let the mass of CaCO3 =xg ,so the mass of MgCO3 = 1.84-xg

x gram of CaCO3 will give CaO = 56 x /100

similarly 1.84 -x g will give MgO = 40(1.84 -x)/ 84 g

Total mass =0.96g

so, 0.56 + 40(1.84 -x)/ 84 g =0.96

x= 1

% of CaCO3 = 1/1.84 = 54.35

% of MgCO3 = 100- 54.35 = 45.65  ..........☺☺!!


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HOPE IT HELPS YOU.....!!❤☺

Answer 2

Let the mass of CaCO3 =xg ,so the mass of MgCO3 = 1.84-xg

x gram of CaCO3 will give CaO = 56 x /100

similarly 1.84 -x g will give MgO = 40(1.84 -x)/ 84 g

Total mass =0.96g

so, 0.56 + 40(1.84 -x)/ 84 g =0.96

x= 1

% of CaCO3 = 1/1.84 = 54.35

% of MgCO3 = 100- 54.35 = 45.65  .......