Question

Heya mates ,
Please solve this !
In rhombus ABCD diagonals AC and BD intersect each other at point O.
If cosine of angle CAB is 0.6 and OB is 8cm ,.find the length of the side and the diagonals of the rhombus ?

Plz dont spam..........___/\___​

Answer 1

Answer:

AB=BC=CD=AD=13.33

AC=64 BD=16

Step-by-step explanation:

COS(A)=0.6

OB/AB=0.6

8/AB=0.6

AB=13.33(after calculation)

As WKT, TRI(AOB) is a right angled triangle

So, BY PYTHAGORAS THEOREM

AB*2=AO*2+OB*2

(40/3)*2=AO*2+8*2

AO*2=1024

AO=32

AC=AO+OC

AC=2AO. (AO=OC)

AC=64

FOR A RHOMBUS ALL SIDES ARE EQUAL

SO, AB=BC=DC=AD=13.33 OR 40/3