Question

heya mates.....plz plz plz..solve it...

its urgent


50th question

Answer 1

Resistance b/w A and B:

=10+150/8+10

=160+150/8

=310/8

=38.7ohms

PLS MARK THE BRAINLIEST.

Answer 2

Answer:

The resistance between A and B is 38.75 ohm.

Explanation:

Given that,

According to figure,

$R_{1}=10\Omega$

$R_{2}=20\Omega$

$R_{3}=10\Omega$

$R_{4}= 20\Omega$

$R_{5}=10\Omega$

$R_{6}=30\Omega$

The resistance R₂,R₃ and R₄ are connected in series

Then, The equivalent resistance will be

$R= R_{2}+R_{3}+R_{4}$

$R=20+10+20$

$R= 50\Omega$

Now, The resistance R and R₆ are connected in parallel

The equivalent resistance will be

$\dfrac{1}{R'}=\dfrac{1}{R}+\dfrac{1}{R_{6}}$

$\dfrac{1}{R'}=\dfrac{1}{50}+\dfrac{1}{30}$

$R'=\dfrac{150}{8}$

Now, The resistance R_{1}, R' and R_{4} are connected in series

The equivalent resistance will be

$R''=R_{1}+R'+R_{4}$

$R''=10+\dfrac{150}{8}+10$

$R''= 38.75\Omega$

Hence, The resistance between A and B is 38.75 ohm.