Question

HEYA MATES ❤️

QUESTION :

Two years ago, Salim was thrice as old as his daughter and six years later he will be four years older than twice her age. How old are they now? ✔️✌️

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Answer 1

Heya!

Here is ur answer...

__________________________

let,

The age of salim be "x"

the age of his daughter be "y"

According to the Hypothesis,

Two years ago, Salim was thrice as old as his daughter

So,

Two years ago,

The age of salim was (x-2)

the age of his daughter was (y-2)

Therefore,

(x-2) = 3(y-2)

x-2 = 3y-6

x = 3y-6+2

x = 3y-4 ............(1)

But,

Six years later, he will be 4 years older than twice the age of her daughter

So, six years later,

Age of salim will be = (x+6)

Age of his daughter = (y+6)

Therefore,

(x+6) = 2(y+6)+4

x+6 = 2y+12+4

x = 2y+16-6

x = 2y+10..............(2)

From (1) and (2),

3y-4 = 2y+10

3y-2y = 10+4

y = 14

By sub. y = 22 in eq.(1),

x = 3(14)-4

x = 42-4

x = 38

Hence, present age of..

salim = 38

his daughter = 14

Hope it helps u..

Answer 2

Answer:

Hope it's Helpful for you...

Answer 3

Answer:

14 years, 38 years

Step-by-step explanation:

Let the age of daughter two years be x years.

Two years ago:

Age of Salim = 3x

6 years later:

Age of daughter = x + 2 + 6 = x + 8

Age of Salim = 3x + 2 + 6 = 3x + 8.

Given that 6 years later he will be 4 years older than twice her age.

⇒ 3x + 8 = 2(x + 8) + 4

⇒ 3x + 8 = 2x + 16 + 4

⇒ 3x + 8 = 2x + 20

⇒ x = 12

Therefore:

Present age of daughter = x + 2 = 14

Present age of Salim = 3x + 2 = 38

Hope it helps!