Question

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Solve it plss♥

A train covers a distance of 90 kms of a uniform speed . It would have taken 30 minutes less if the speed had been 15 km/hr calculate the original distance duration of the journey

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Answer 1

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Answer 2

Answer:

original speed of the train =45 km/hr.

Step-by-step explanation:

Given :-

▶Distance =90 km

Let the original speed of the train =×km/hr.

▶Time taken to travel =90/×hr.

Time taken to travel =90 / (×+15)hr.

Now, A /Q

90 /×=90 / (×+15 )+1/2.

▶90 /×-90 / (×+15 )=1/2.

▶90 { 1/×-1 / (×+15 ) }=1/2.

▶×+15 -×/× (×+15 )=1/2 ×1/90.

▶×/15 ( ×+15 )=180.

▶× (×+15 )=15 ×180 =2700.

▶x +15 ×-2700 =0

▶x+60 ×-45 ×+2700 =0

▶ (×+60 ) (×-45 )=0.

▶×+60 =0 or ×-45 =0.

▶×=45 or -60

{ Speed can't be negative. }

⏩ Original speed =45 km /hr.

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Onlystudies98 ❤

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