Question

Heya Mates Solve this..plzz

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Answer 1

Hey mate your answer

Assuming a horizontal ground.

Let A and B be the points on the top of poles a and b, respectively. Let C and D be the points on the bases of the poles.

Draw a line segment from the point of intersection (call it H) perpendicular to the ground. Call the point of intersection of the line segment and the ground P.

Then AC = a, BD = b and CD = p. Let HP = h (height of the point of intersection), CP = x and PD = p - x (because CP + PD = CD = p).

Notice that triangles ACD and HPD are similar. Then

AC / CD = HP / PD or a / p = h / (p-x)

Triangles BDC and HPC are also similar. Then

BD / DC = HP / PC or b / p = h / x

Then

p - x = hp / a

x = hp / b

Adding the equations,

p = hp / a + hp / b

Dividing both sides by p,

1 = h / a + h / b

1 = h[(a + b) / ab]

Solving for h,

h = ab / (a + b)

Hope it helps to you!!!!!

Answer 2

Let AB and CD be two poles of height a and b metres respectively such that the poles are p metres apart i.e. AC= p metres. Suppose the lines AD and BC meet at O such that OL =h metres.

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Hence, the height of the intersection of the lines joining the top of each pole to the foot of the opposite pole is ab/(a+b) metres.