Question

heya!!!
✨ maths Aryabhatta ✨

if the area of a trapezium is 28 m², and two parallel sides are 8 m and 60 dm respectively, find the altitude.

Answer 1

Hi , there !!!

here is your answer !!

area of trapezium = 1/2 ( sum of || sides ) × height

sides
=> 60 dm = 6/ 10 = 6 cm
=> 8 m

=> 28 m²= 1/ 2 = ( 6 +8 ) × height

=>. 56 = 14 × height

height = 4 m .

hope it helps !!

thanks !!

Ranjan Kumar

Answer 2

Hola User!!

Your answer :-

$area = 28 {m}^{2} \\ parallel \: sides \: = 60dm = \frac{60}{10} m = 6m \\ and \: 8m \\let \: height \: = h \\ \\ sol. => area = \frac{1}{2} (sum \: of \: parallel \: sides ) \times height \\ \\ = > 28 {m}^{2} = \frac{1}{2} (6 + 8)m \times h \\ \\ = > 28 = \frac{1}{2} \times 14 \times h \\ \\ = > 28 \times 2 \times \frac{1}{14} = h \\ \\ = > 4m = h$



Hope it helps!!

☆ Regards @e ☆