Question

HEYA
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#NEED FULL EXPLANATION
#20 POINTS
#NO SPAM

..THANK YOU

Answer 1

Hey mate ___________.

Here is your answer ___________.

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Let
h=height of the building

The acceleration due to gravity is
g=9.8ms^−2

The distance travelled by the stone from the top of the building is
=lm

The distance travelled by the stone from the top of the building is
=(h−l)m

Apply the equation of motion,
s=ut+1/2at^2

The time is
t=3s

For the stone thrown from the top of the building
l = 0×3+1/2×9.8×3^2=44.1m

For the stone thrown from the bottom of the building
h−l=20×3−1/2×9.8×3^2=60

−44.1m = 15.9m

Therefore,
the height of the building is
h=15.9 +44.1 = 60m

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Hope it helps you ☺☺☺

Answer 2

Ahoy mate..!!


Let
h=height of the building

The acceleration due to gravity is
g=9.8ms^−2

The distance travelled by the stone from the top of the building is
=lm

The distance travelled by the stone from the top of the building is
=(h−l)m

Apply the equation of motion,
s=ut+1/2at^2

The time is
t=3s

For the stone thrown from the top of the building
l = 0×3+1/2×9.8×3^2=44.1m

For the stone thrown from the bottom of the building
h−l=20×3−1/2×9.8×3^2=60

−44.1m = 15.9m

Therefore,
the height of the building is
h=15.9 +44.1 = 60m


Hope it helps..✌️✌️