Question

heya ......


need urgent help

Answer 1

Hope u like my process.
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=> Mean of the following data means the average with the values of the average Data.

Now..

The formula can be written as

$= > mean = \frac{ total \: \: f_{x} }{total \: \: x}$


$= > f_{x} = (10 \times 6) + (15 \times 8) + (20 \times p) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: + (25 \times 10) + (30 \times 6) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = 60 + 120 + 20p + 250 + 180 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = \bf 610 + 20p \\ \\ = > x = 6 + 8 + p + 10 + 6 = \bf30 + p$
So..

The required mean = 20.2

So..

$= > \frac{610 + 20p}{30 + p} = 20.2 \\ \\ = > 610 + 20p = 606 + 20.2p \\ \\ = > 20.2p - 20p = 610 - 606 \\ \\ = > 0.2p = 4 \\ \\ = > \boxed{ p = \frac{4}{0.2} = \bf \underline{20}}$

So the required value of p =20

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