Question

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Answer 1

Answer:

$\red {Number \: T-shirts \: left} \green {= x+y}$

Step-by-step explanation:

$Number \: of \:players \: in \:a \:team = 11$

$Number \: T- shirts \: purchased \: first \:time \\= 10x + y$

$Number \: T- shirts \: purchased \: second \:time \\= 10y + x$

$Total \: T-shirts = 10x + y + 10y + x \\= 11x + 11y \\= 11(x+y)$

/* If Total T-shirts distributed to players equally then

$Number \: T-shirts \: left \\= \frac{Total\: T-shirts}{Number \: players }\\= \frac{11(x+y)}{11} \\= x+y$

Therefore.,

$\red {Number \: T-shirts \: left} \green {= x+y}$

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Answer 2

Given :

There are 11 players.

They purchased 10x+y t-shirts initially and then 10y+x t-shirts

To Find :

Number of T-shirts bought by each player

Solution:

Total number of players= 11

Number of T-shirts purchased initially = 10x+y

Number of T-shirts purchased again = 10y+x

Total no. of T-shirts purchased=10x+y+10y+x=11x+11y

Number of T-shirts given to each player = \frac{11x+11y}{11}

                                                                  =x+y

Hence each one will get (x+y) t-shirts