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CLASS- X
CH-8
TRIGONOMETRY
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Anonymous:
a=60
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Hi mate here is ur query
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dividing by cosA in numerator and denominator
we find the expression
(1-tanA)/ (1+tanA) = (1-√3)/(1+√3)
comparing right and left side
we find
tanA=tan60°
tanA=√3
hence angle A=60°
____________________
___________________
dividing by cosA in numerator and denominator
we find the expression
(1-tanA)/ (1+tanA) = (1-√3)/(1+√3)
comparing right and left side
we find
tanA=tan60°
tanA=√3
hence angle A=60°
____________________
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