Question

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CLASS - X

For what value of k will k+9, 2k-1 and 2k+7 be the consecutive terms of an A.P. ?
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Answer 1

this is your answer best.

Answer 2

Let,

k + 9 = a

2k - 1 = b

2k + 7 = c

To be in AP,

a + c = 2b

(k + 9) + (2k + 7) = 2(2k - 1)

k + 9 + 2k + 7 = 4k - 2

3k + 16 = 4k - 2

3k - 4k = - 2 - 16

- k = - 18

k = 18

For k = 18, the terms k+9 , 2k - 1 , 2k + 7 are in AP