Question

Heya

P. T

(2 sin A + sin 2 A) / (2 sin A - sin 2 A) = cot^2 A /2

Answer 1

sin^2x+sin^2x cot^2x

= sin^2x*(1+cos^2x/sin^2x)

= sin^2x*((sin^2x+cos^2x)/sin^2x)

= sin^2x*(1/sin^2x)

= sin^2x/sin^2x

= 1

Answer 2

solution is attached above......