Heya!!!!
Please aid me with this question by providing sufficient explanation along. :-)
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from c to d is 2 Amp. While current through each resistance is 1 A.
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DiyanaN:
thank u sir
my doubt was that wont 2 ampere b answer?
in ans key , ans is 1A
@physicsteacher: it is not required to calculate effective resistance of 6 Ω and 9 Ω...
Solvable in one step.
I just solved it to illustrate use of Kirchoff's rule so that any other question of this type might not pose any problem to the user.
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Very simple to solve in two steps.
Effective resistance across CD = 6/2 = 3 Ω.
As voltage across ACD = 12V, current through it: 12V /(3+3)Ω = 2 A.
As two resistances between CD are equal, 1 Amp flows in each.
Effective resistance across CD = 6/2 = 3 Ω.
As voltage across ACD = 12V, current through it: 12V /(3+3)Ω = 2 A.
As two resistances between CD are equal, 1 Amp flows in each.
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tysm sir
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