Question

☺ Heya ☺

Please answer this question:-

Q. A copper coin is kept immersed in a solution of silver nitrate for some time.

What will happen to the coin and the colour of the solution?​

Answer 1

⭐Hola User________________

⭐Here is Your Answer....!!!

________________________

↪Actually welcome to the concept of the Reactivity Series of the Elements

↪Since here , we know that , in the Reactivty series

↪Copper is placed above the Silver Element , thus it is more reactive than the Silver ..

↪Now moving forward towards the DISPLACEMENT REACTION taking place in the solution , here the copper will easily displace the Ag that is silver from the solution and the Copper coin will be turned with a Silver coated coin

↪The reaction will be as ..

〽Cu2+ (s) + AgNO3 ( aq) --------》 Ag1+ (s) + Cu (NO3)2 (aq)


↪The solution will be changed from a COLOURLESS SOLUTION to a BLUE SOLUTION ,since copper nitrate is coloured solution
⭐__________________________

〽⭐〽

Answer 2

$\huge\underline\mathfrak\green{Hola!!}$

$<b>Copper is placed above the silver in the reactivity series which indicates that copper is more reactive than silver .when copper coin or strip is kept immersed in a solution of silver nitrate (AgNO3),silver from its solution will deposit on copper coin. 2AgNO3(aq)+Cu→2Ag+Cu(NO3)2(aq) Copper slowly displaces silver from the AgNO3 solution and the colour of the solution. changes from colourless to blue due to formation of copper nitrate .The copper coin will disappear and silver will precipitate out. </b>$
_____________________________
$<marquee bgcolor=pink behavior=alternate>❤️Thanks❤️</marquee>$