Question

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An aqueous solution of glucose has mole fraction 0.1. The molality of solution will be ??????

Answer 1

Mole fraction of glucose = 0.1

An aqueous solution of glucose has mole fraction 0.1.

Mole fraction of solution = 1

So, Mole fraction of water = 1 - 0.1

⇒ 0.9

Now,

Molarity= Number of moles of solute present in 1 liter of solution.

$\sf{Molarity}\:=\:\frac{Number\:of\:moles\:of\:solute}{Mass\:of\:solvent\:(in\:kg)}$

Also, we know that

Molar Mass of H20 = 18 g/kg

So,

$\sf{Mass\: of\: H_20\:=\:\dfrac{0.9\:\times\:18}{1000}}$

⇒ $\sf{\dfrac{16.2}{1000}}$

⇒ $\sf{0.0162}$ kg

Now,

$\sf{Molarity}\:=\:\dfrac{0.1}{0.0162}$

⇒ $\sf{6.17}$ M

Answer 2

$\huge{\mathfrak{\red{\underline{Answer :- }}}}$

Given :-

An aqueous solution of glucose has mole fraction 0.1.

Solution :-

Mole fraction of solution = 1

So, Mole fraction of water = Mole fraction of solution - Mole fraction of glucose

= 1 - 0.1 = 0.9

Number of moles of solute present in 1 liter of solution.

Molarlity = Number of moles of solute / Mass of solvent

We know that

${Molar \:Mass \: of\: H_{2}0 = 18 u}$

$\rule{200}{2}$

Mass of H20 = (0.9×18) / 1000

⇒ 16.2 / 1000

⇒ 0.0162 kg

Now,

Molarlity=0.1 / 01620

⇒ 6.17 M

$\huge{\boxed{\red{6.17 \: M}}}$

$\rule{200}{2}$

Extra Information:-

Number of moles of solute present in 1 liter of solution is known as morality