Heya _____
Please solve the question given below
A heap of wheat is in the form of a cone whose diameter is 10.5 and height is 3m. Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.
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Answered by
4
Hi ,
Dimensions of the conical shaped heap
Diameter = d = 10.5 m
Radius = r = d / 2
r = 10.5 / 2 = 5.25 m
i ) volume of the heap = volume of the cone
V = ( pi × r ^2 × h ) /3
= (22 / 7 ) × ( 5.25 )^2 × 3 / 3
= 86.625 cubic cm
ii ) let the slant height of the cone = l cm
l^2 = r^2 + h^2
= 3^2 + ( 5.25 )^2
= 9 + 27.5625
= 36.5625
Therefore ,
l = 6.046 ( approx)
The area of the canvas required to from rain
= curved surface area of the cone
= pi × r × l
= (22/ 7 ) × 5.25 × 6.046
= 697.62 / 7
= 99.66 cm^2
I hope this helps you.
Dimensions of the conical shaped heap
Diameter = d = 10.5 m
Radius = r = d / 2
r = 10.5 / 2 = 5.25 m
i ) volume of the heap = volume of the cone
V = ( pi × r ^2 × h ) /3
= (22 / 7 ) × ( 5.25 )^2 × 3 / 3
= 86.625 cubic cm
ii ) let the slant height of the cone = l cm
l^2 = r^2 + h^2
= 3^2 + ( 5.25 )^2
= 9 + 27.5625
= 36.5625
Therefore ,
l = 6.046 ( approx)
The area of the canvas required to from rain
= curved surface area of the cone
= pi × r × l
= (22/ 7 ) × 5.25 × 6.046
= 697.62 / 7
= 99.66 cm^2
I hope this helps you.
Answered by
6
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arjun6068:
solved it soo quick!!!!
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