Question

☺Heya,☺

Please solve this question:-

Q. Find the sum of integers between 100 and 200:

(1) Divisible by 9

(2) Not divisible by 9​

Answer 1

♡hello mate♡

Answer:

Sum =13167

Step-by-step explanation:

First we find how many numbers between 100 and 200 divisible by 9

108,117,126.... 198 and so on

So a=108

l=198

n= ?

nth term= a + (n-1)d

198= 108+(n-1)9

198= 108+9n-9

198-99= 9n

99/9= n

n= 11

Now, sum of n terms

Sum of first 11 terms= 11/2(108+198)

=11/2(306)

=11×153

=1683

The sum integers between 100 and 200 that are not divisible by 9.


First term (a) = 108

Common Difference (d) = 9

Last term (l)=198

Formula:

198=108+(n-1)9

n=11

Now we find sum of these 11 terms

Formula:

Sum of 11 term = 1683

Now we find the sum of series 101,102,103,.........,199

Sum of 99 terms = 14850

Sum of integers between 100 and 200 not divisible by 9 = 14850 - 1683 = 13167


Hope it helps uu...!!!

#Dramaqueen⭐

Answer 2

Hey there !!!!

1)-108 is the smallest three digit number divisible by 9.

108,117,126...............198

Above series starts with 108 and ends with 198

Sum of this series S= n(first term+last term)/2

198=a+(n-1)d

198=108+(n-1)9

198=108+n-9

n=11

Sum= 11(198+108)/2=1683

2)-

sum of number between 100 and 200 which are not divisible by 9 = (sum of numbers between 100 and 200) - (sum of number which are divisible by 9 between 100 and 200) = 14850-1683 = 13167.

please mark as brainliest dude!!

GOOD QUESTION!!!