Question

Heya,

Pls ans this!!
Rain is falling vertically with a speed 35m/s. A woman rides a bicycle with a speed 12m/s in east to west direction. What is the direction in which she should hold umbrella?

Answer 1

Here, we use the concept of Relative Motion.


We know that the rain is falling vertically. And the woman is moving towards West.


Now, we have to find the velocity of Rain with respect to (w.r.t.) the Woman.


For this, we use the Triangular Law of Vector Addition.

From that, we come to know that the woman must hold the umbrella towards the west, at an elevation of arctan (35/12) from the horizontal.


Hope it helps,
Purva
Brainly Community

Answer 2

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HERE IS YOUR ANSWER ☞
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$velocity \: of \: the \: rain \: = v _{r} \: = 35 \: m {s}^{ - 1} \\ \\ velocity \: of \: the \: wind \: = \: v _{w} = 12 \: m {s}^{ - 1} \\ \\ now \: \: \\ \\ direction \: of \: the \: umbrella \: w. \: r. \: to \: ground \: = > \\ \\ = > \: tan( \alpha ) = \frac{v _{r} }{v _{w} } \\ \\ = > tan \alpha \: = \: \frac{35 \: m {s}^{ - 1} }{12 \: m {s}^{ - 1} } \\ \\ = > tan \alpha \: = \: \frac{35}{12} \\ \\ than \\ \\ = > \alpha = {tan}^{ - 1} \frac{35}{12} \: \: \: \: .......answer \\ \\ \\ hence \: the \: woman \: should \: \\ hold \: the \: umbrella \: \\ w. \: r. \: t \: the \: ground \: an \: angle \: = \: {tan}^{ - 1} \frac{35}{12}$


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