Heya plzz explain well ! will be marked brainliest!
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heya...!!!!
a² + b² + c² - ab - bc - ca = 0
=> 2(a² + b² + c² - ab - bc - ca) = 2×0
=> 2a² + 2b² + 2c² - 2ab - 2bc - 2ca = 0
=> (a² + b² - 2ab) + (b² + c² - 2bc) + (c² + a² - 2ca) = 0
=> (a - b)² + (b - c)² + (c - a)² = 0
=> (a - b)²= 0
=> a = b
(b - c)² = 0
=> b = c
(c - a) ² = 0
=> c = a
hence ,
a = b = c
hence, option (d) is correct
a² + b² + c² - ab - bc - ca = 0
=> 2(a² + b² + c² - ab - bc - ca) = 2×0
=> 2a² + 2b² + 2c² - 2ab - 2bc - 2ca = 0
=> (a² + b² - 2ab) + (b² + c² - 2bc) + (c² + a² - 2ca) = 0
=> (a - b)² + (b - c)² + (c - a)² = 0
=> (a - b)²= 0
=> a = b
(b - c)² = 0
=> b = c
(c - a) ² = 0
=> c = a
hence ,
a = b = c
hence, option (d) is correct
kanikamalhans:
thaank uu so much!
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