Question

Heya plzz explain well ! will be marked brainliest!

Answer 1

Method - (1):

$Given : \frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab}$

$\frac{a^2 * a + b^2 * b + c^2 * c}{abc}$

$\frac{a^3 + b^3 + c^3}{abc}$

Given that a + b + c = 0, then we know that a^3 + b^3 + c^3 = 3abc.

$\frac{3abc}{abc}$

3.



Method - (2):

Given a + b + c = 0

a + b = -c 

Now,

On cubing both sides, we get

(a + b)^3 = (-c)^3

a^3 + b^3 + 3ab(a + b) = (-c)^3

a^3 + b^3 + 3ab(-c) = (-c)^3

a^3 + b^3 + c^3 = 3abc

(a^3 + b^3 + c^3)/abc = 3

$\frac{a^3}{abc} + \frac{b^3}{abc} + \frac{c^3}{abc} = 3$

$\frac{a^2}{bc} + \frac{b^2}{ac} + \frac{c^2}{ab} = 3.$



Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks